2[3-2(z+4)]=4(4-z)

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Solution for 2[3-2(z+4)]=4(4-z) equation: 


Simplifying
2[3 + -2(z + 4)] = 4(4 + -1z)

Reorder the terms:
2[3 + -2(4 + z)] = 4(4 + -1z)
2[3 + (4 * -2 + z * -2)] = 4(4 + -1z)
2[3 + (-8 + -2z)] = 4(4 + -1z)

Combine like terms: 3 + -8 = -5
2[-5 + -2z] = 4(4 + -1z)
[-5 * 2 + -2z * 2] = 4(4 + -1z)
[-10 + -4z] = 4(4 + -1z)
-10 + -4z = (4 * 4 + -1z * 4)
-10 + -4z = (16 + -4z)

Add '4z' to each side of the equation.
-10 + -4z + 4z = 16 + -4z + 4z

Combine like terms: -4z + 4z = 0
-10 + 0 = 16 + -4z + 4z
-10 = 16 + -4z + 4z

Combine like terms: -4z + 4z = 0
-10 = 16 + 0
-10 = 16

Solving
-10 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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